GearLab gears & robot gearboxes
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5. Tooth forces and flank pressure

The force between two involute teeth acts along the line of action, at the working pressure angle. Resolve it and you get the two components the shaft and its bearings actually feel:

Ft = 2 Td     Fr = Ft · tan αw     Fn = Ftcos αw

The radial component does no work — it just pushes the wheels apart and loads the bearings. That is what the gear entry in ShaftLab wants from you.

Pitting: the flank rating

A gear tooth does not usually break. It pits: the Hertzian pressure at the contact line fatigues the surface until flakes come away. ISO 6336-2 writes that pressure as a nominal stress multiplied by a set of factors:

σH0 = ZH · ZE · Zε · Zβ · √( Ftd1 b · u + 1u )ISO 6336-2
FactorWhat it carriesSpur, 20°, steel
ZHthe curvature of the flanks at the pitch point2.495
ZEthe elasticity of the material pair189.8 √MPa
Zεload sharing between teeth0.87 – 0.90
Zβhelix angle1 (spur)
ZH = √( 2 cos βb cos αwtcos² αt · sin αwt )     ZE = ( π ( 1 − ν₁²E₁ + 1 − ν₂²E₂ ) )−1/2ISO 6336-2

What the square root is telling you

σH goes with √Ft, not with Ft. Four times the torque is only twice the flank stress. It also goes with 1/√b, so doubling the face width buys 30 %, not 50 %. This is the signature of a contact problem and it is why gear sizing feels unlike beam sizing: the cheap lever is the diameter, which appears both in Ft and in d₁.

What this rating does not include. The full ISO 6336 method multiplies by KA, Kv, K and K — application, dynamic, and two load-distribution factors — and then compares against a permissible stress built from life, lubricant, roughness, size and work-hardening factors. GearLab applies KA only and compares against σHlim directly. Treat the result as a comparison tool between designs, not as a certificate.
Try it

A case-hardened robot pinion at the first stage of a joint: 3 N·m at 3000 rpm into a 1:4 pair.

Formulas in this chapter

F_t, F_r, F_n — spur gear tooth forces
F_t = 2T/d, F_r = F_t tan α_w, F_n = F_t/cos α_w [N] statics
σ_H0 — nominal contact (flank) stress
σ_H0 = Z_H Z_E Z_ε Z_β √(F_t/(d₁ b) · (u+1)/u) [MPa] ISO 6336-2
Z_H — zone factor
Z_H = √(2 cos β_b cos α_wt / (cos²α_t sin α_wt)); 2.495 for spur at 20° [—] ISO 6336-2
Z_E — elasticity factor
Z_E = (π((1−ν₁²)/E₁ + (1−ν₂²)/E₂))^(−1/2); 189.8 √MPa steel/steel [√MPa] ISO 6336-2