BearingLab rolling bearing life
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2. From revolutions to hours

L₁₀ comes out in millions of revolutions, which is the honest unit — a bearing does not know what time is. But nobody specifies a machine in revolutions, so:

L10h = 10660 · n · ( CP )p   [hours, n in rpm]ISO 281

Note what this does and does not change. Doubling the speed halves the hours and leaves the revolutions untouched. A bearing in a slow robot joint can be tiny and still last decades; the same bearing at 10 000 rpm is a consumable.

What life to design for

ApplicationTypical L₁₀h
Household appliance, intermittent1 000 – 4 000 h
Machine tool spindle10 000 – 30 000 h
Industrial robot joint20 000 – 40 000 h
Continuous industrial drive, 24/750 000 – 100 000 h

Those are conventions, not physics — they encode how much downtime the application tolerates. 8760 hours is one calendar year of continuous running, which is the number worth keeping in mind when a figure like 40 000 h stops meaning anything.

Reliability costs life, steeply

L₁₀ is a 90 % figure. Wanting better multiplies it by a factor well below one:

Lnm = a1 · aISO · L10ISO 281
Reliability90 %95 %96 %97 %98 %99 %
a₁1.000.620.530.440.330.21

Going from 90 % to 99 % throws away four fifths of the calculated life. In a robot with six joints that matters more than it looks: if each joint is 90 % reliable over the design life, the arm as a whole is 0.9⁶ ≈ 53 %.

Try it

A robot joint bearing at 30 rpm — slow, so the hours pile up even at a modest load ratio.

Formulas in this chapter

L₁₀ₕ — basic rating life in hours
L₁₀ₕ = (C/P)^p · 10⁶/(60 n) [h] ISO 281
Lₙₘ — modified rating life
Lₙₘ = a₁ · a_ISO · L₁₀; a₁ = 1.0 / 0.62 / 0.53 / 0.44 / 0.33 / 0.21 at 90…99 % [Mrev] ISO 281