FrameLab bent beams & frames
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This is a static copy of the chapter for search engines. The interactive version has animated figures, check questions, and buttons that load the example into the calculator.

What happens at a corner

This is the heart of the subject. Take a rigid corner with no load applied exactly on it, cut the bar immediately before and immediately after, and write equilibrium for the (massless, infinitesimal) piece of corner in between.

Cut just before the corner Cut just after it N₁ V₁ M₁ N₂ V₂ M₂ M₂ = M₁ N₂ = V₁ · V₂ = −N₁ (for the −90° turn shown) the moment carries straight through, the forces swap roles
An unloaded corner is just a change of direction. The bending moment passes through unchanged, but what was axial force on one side becomes shear on the other — and vice versa.

The three rules

Let Δα = α₂ − α₁ be the kink angle from member 1 to member 2. Resolving member 1’s internal force into member 2’s local axes gives:

N₂ = N₁·cos Δα − V₁·sin Δα
V₂ = N₁·sin Δα + V₁·cos Δα
M₂ = M₁

The rotation turns the other way than you might expect, because a positive V acts along −n on a +t face: the transmitted force vector is N·t − V·n, and it is that vector which rotates. If the signs ever confuse you, read the magnitudes off the diagram drawn on the structure — that picture never depends on a convention.

Three consequences worth memorising:

  1. M is continuous. A rigid unloaded corner never changes the bending moment. If your hand calculation shows a jump in M at a corner, you have either applied a moment there or made a mistake.
  2. N and V rotate into each other. At a right-angle corner the swap is total: |N₂| = |V₁| and |V₂| = |N₁|, with the signs following the direction of the turn (Δα = −90° gives N₂ = V₁, V₂ = −N₁; Δα = +90° gives N₂ = −V₁, V₂ = N₁). The shear that the beam delivers to the corner leaves as pure axial force in the column.
  3. Nothing is lost. The corner is a transmitter, not a source. Whatever arrives, leaves — just re-labelled.

Why the diagrams jump

Plotted against the developed length s, N(s) and V(s) show a step at every corner while M(s) runs through smoothly. That step is not a numerical artefact; it is rule 2 above. When you see it on the chart, you are looking at the geometry doing its work.

The corner is also the most stressed point

In almost every bent bar, the largest bending moment sits at a corner — because the corner is where the lever arm from the load is longest and where two members hand their moments to each other. Add to that:

  • the corner usually carries the largest axial force too, so σ = N/A + M/W peaks there;
  • real corners have welds, notches or bends, all of which raise the local stress well above the beam value;
  • the beam theory that FrameLab uses assumes plane sections stay plane, which is not true within roughly one section depth of a sharp corner.
⚠ Treat the computed stress at a corner as the nominal stress. For a real joint you still need a stress-concentration factor, a weld check, or a local finite-element model. FrameLab tells you how big the internal actions are; it does not detail the joint for you.
Example — watch the swap

An L-bracket loaded horizontally instead of vertically. The arm now carries pure axial force and the column pure bending — the exact opposite of the vertical load case.

Formulas in this chapter

M, N, V — what a rigid corner does to the internal actions
M continuous; N and V exchange as the local axes rotate [N·m, N] equilibrium of the joint